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TwinOtterFan
Posts: 419
Joined: Sat Feb 22, 2020 5:11 pm
Location: Onoway, AB

Hey all, I cannot figure out how to answer this question. Could someone help me? This will probably be really easy for you guys but seriously I have tried it about 5 times and cannot get it. I'm just at the point of pure frustration now.

The Question:
Question 8.jpg
So to me, if I take the altitude from the airport data 628' factor in the altimeter setting of 29.85 I get an additional 70' so a pressure altitude of 698' then its 18 degrees so that is 3 above 15 so 3x120 (the rule of thumb) is 360+698 = 1058?

Anyway I have accepted for tonight I am clearly to stupid to be a pilot, anyone that can help would be much appreciated.

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CpnCrunch
Posts: 53
Joined: Thu Jan 16, 2020 3:59 am

I've never heard of a rule of thumb for DA, and you won't need it for any written exams (as you'll have your e6b). But as for your error: it's not actually 3 degrees above standard at the airport...
TwinOtterFan
Posts: 419
Joined: Sat Feb 22, 2020 5:11 pm
Location: Onoway, AB

CpnCrunch wrote:
Thu Jul 08, 2021 12:59 am
I've never heard of a rule of thumb for DA, and you won't need it for any written exams (as you'll have your e6b). But as for your error: it's not actually 3 degrees above standard at the airport...
I am clearly missing something here.... I used 15 as standard plus the 18 they put in that chart?
CpnCrunch
Posts: 53
Joined: Thu Jan 16, 2020 3:59 am

TwinOtterFan wrote:
Thu Jul 08, 2021 1:22 am


I am clearly missing something here.... I used 15 as standard plus the 18 they put in that chart?
No, 15 is wrong. Think about it.
TwinOtterFan
Posts: 419
Joined: Sat Feb 22, 2020 5:11 pm
Location: Onoway, AB

I wasn't decreasing the standard air by 2 degrees per 1000'...... but I'm still not getting 1200'

So 698' is about 1.396 degrees below 15. So 13.6 degrees.
Giving me 18 - 13.6 = 4.4 degrees.

4.4 x 120 = 528 + 698 = 1226'
CpnCrunch
Posts: 53
Joined: Thu Jan 16, 2020 3:59 am

TwinOtterFan wrote:
Thu Jul 08, 2021 2:47 am
I wasn't decreasing the standard air by 2 degrees per 1000'...... but I'm still not getting 1200'

So 698' is about 1.396 degrees below 15. So 13.6 degrees.
Giving me 18 - 13.6 = 4.4 degrees.

4.4 x 120 = 528 + 698 = 1226'
Yeah, so the answer is 1200. It's a rule of thumb, so it's not going to be exact. Just choose the closest answer.
TwinOtterFan
Posts: 419
Joined: Sat Feb 22, 2020 5:11 pm
Location: Onoway, AB

Thank you, I probably should have just taken a break but my day was shit, and my night sucked and I wanted at least one victory.
TwinOtterFan
Posts: 419
Joined: Sat Feb 22, 2020 5:11 pm
Location: Onoway, AB

One more question about this, when calculating the standard temperature do you use the altitude of the airport on the map or the altitude pressure altitude? So for this example the altitude was 628, but the pressure altitude was 698.
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