Comparing energy on a 737, as that was the easiest plane to find tire weights from. Looking at main wheel tires:Colonel wrote: ↑Tue Mar 24, 2020 2:09 pmAn interesting question. From a physics standpoint, if the momentum of just the tire's mass
rotating on the rim is sufficient to rotate the tire on the wheel and shear the valve (when
brakes are applied to the wheel) ...
What about during heavy braking? The entire weight of the aircraft would try to rotate the
tire on the rim, and shear the valve, correct?
Which exerts more force? The mass of the spinning tire, or the entire aircraft? From a kinetic
energy standpoint, how fast would the tire have to spin, for the force to be equal? Obviously
a tire rotating at 1 mph would be no problem. At 1000 mph?
We need Photofly. He eats this shit with a spoon, and has four degrees. I only have one,
and I am also much lazier :^)
* Tire weight: 94 kg (source: https://www.bridgestone.com/products/sp ... 21_01.html)
* Tire diameter: 44 inch => 1.1 m, tire radius r of 0.55 m
* Speed during landing: 155 knots, or 290 km/h (80 meter per second)
At this speed, a tire will rotate 23.3 times per second, which is a radial velocity (omega) of 144 radians/s
If we simplify the tire as a circle with all the mass of the circle on the outside, the rotational kinetic energy becomes:
KEr = 1/2 * M * r^2 * omega^2 = 294 kJ
* Amount of main wheels on a 737: 4
* Let's assume a mass of 50 ton
Kinetic energy of a plane in that configuration: 160 MJ. Per wheel, that gives 40 MJ.
Even if more than half of the braking happens aerodynamically or with thrust reverse, there is still much more energy being dissipated during the landing roll than during a brake application in the air.
For a movement of the tire around the rim, energy is not the only element to the story. It depends more on the impulse/time it takes to dissipate that energy.
If, when airborne, you apply the brakes for 2 seconds, you dissipate 147 kJ/s
If the landing roll takes 40 seconds, and you burn off half the energy with the tires, you get 500 kJ/s
The extra pressure of the weight of the plane on the tire might make it harder for the tire to move, but the difference is still so big that I find it highly unlikely you would ever be able to creep the tire on the rim by gently applying brakes after take-off.
Or, to look at it in a different way: upon touchdown the wheels violently accelerate from zero to over 200kph in a very short time. If they can survive that, a slight tap on the brakes after take off to do the opposite in a longer period of time, should not hurt the wheels at all.